x^2+2x+1=180

Solution for x^2+2x+1=180 equation:

x^2+2x+1=180

We move all terms to the left:

x^2+2x+1-(180)=0

We add all the numbers together, and all the variables

x^2+2x-179=0

a = 1; b = 2; c = -179;
Δ = b2-4ac
Δ = 22-4·1·(-179)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-12\sqrt{5}}{2*1}=\frac{-2-12\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+12\sqrt{5}}{2*1}=\frac{-2+12\sqrt{5}}{2}
$